What are the solutions to the equation solvefor x,r^2=x^2+y^2 ?

The solutions to the equation solvefor x,r^2=x^2+y^2 are x=sqrt(r^2-y^2),x=-sqrt(r^2-y^2)

Find the zeros of solvefor x,r^2=x^2+y^2

The zeros of solvefor x,r^2=x^2+y^2 are x=sqrt(r^2-y^2),x=-sqrt(r^2-y^2)

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solve for

x, r^{2} = x^{2} + y^{2}

x = r^{2} - y^{2}, x = - r^{2} - y^{2}

Solution steps

r^{2} = x^{2} + y^{2}

Switch sides

x^{2} + y^{2} = r^{2}

Move

y^{2}

to the right side

x^{2} = r^{2} - y^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = r^{2} - y^{2}, x = - r^{2} - y^{2}

t, t = \frac{2 a ( b t ^{2} + n )}{3} + \frac{d}{2}

(x - 1)^{2} - 16 = 1

6 n^{2} = - 12 n - 1

x, x^{2} y + x y = 1

6 x^{2} - x - 3 = 0

What are the solutions to the equation solvefor x,r^2=x^2+y^2 ?
The solutions to the equation solvefor x,r^2=x^2+y^2 are x=sqrt(r^2-y^2),x=-sqrt(r^2-y^2)
Find the zeros of solvefor x,r^2=x^2+y^2
The zeros of solvefor x,r^2=x^2+y^2 are x=sqrt(r^2-y^2),x=-sqrt(r^2-y^2)