What are the solutions to the equation 2.4+1y+0.1y^2=0 ?

The solutions to the equation 2.4+1y+0.1y^2=0 are y=-4,y=-6

Find the zeros of 2.4+1y+0.1y^2=0

The zeros of 2.4+1y+0.1y^2=0 are y=-4,y=-6

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2.4 + 1 y + 0.1 y^{2} = 0

y = - 4, y = - 6

Solution steps

2.4 + 1 \cdot y + 0.1 y^{2} = 0

Multiply both sides by

10

24 + 10 y + y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

y^{2} + 10 y + 24 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 24 = 2

y_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 10 + 2}{2 \cdot 1}, y_{2} = \frac{- 10 - 2}{2 \cdot 1}

y = \frac{- 10 + 2}{2 \cdot 1} : - 4

y = \frac{- 10 - 2}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

y = - 4, y = - 6

2 x^{2} - 12 x = - 5 x - 5

4 x^{2} - 40 x + 300 = 0

(\frac{x}{8})^{2} + 12 = x

x^{2} + 7 = 5 x + 1

x^{2} - \frac{11}{35} x - \frac{2}{7} = 0

What are the solutions to the equation 2.4+1y+0.1y^2=0 ?
The solutions to the equation 2.4+1y+0.1y^2=0 are y=-4,y=-6
Find the zeros of 2.4+1y+0.1y^2=0
The zeros of 2.4+1y+0.1y^2=0 are y=-4,y=-6