What are the solutions to the equation (2x-3)^2-8=0 ?

The solutions to the equation (2x-3)^2-8=0 are x=(2sqrt(2)+3)/2 ,x=(-2sqrt(2)+3)/2

Find the zeros of (2x-3)^2-8=0

The zeros of (2x-3)^2-8=0 are x=(2sqrt(2)+3)/2 ,x=(-2sqrt(2)+3)/2

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(2 x - 3)^{2} - 8 = 0

x = \frac{2 2 + 3}{2}, x = \frac{- 2 2 + 3}{2}

Decimal Notation

x = 2.91421 \dots, x = 0.08578 \dots

Solution steps

(2 x - 3)^{2} - 8 = 0

Move

8

to the right side

(2 x - 3)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 3 = 8 : x = \frac{2 2 + 3}{2}

Solve

2 x - 3 = - 8 : x = \frac{- 2 2 + 3}{2}

The solutions to the quadratic equation are:

x = \frac{2 2 + 3}{2}, x = \frac{- 2 2 + 3}{2}

a^{2} - 4 a - 32 = 0

(4 x - 3)^{2} - (x - 1) (x - 9) = 0

x^{2} + 10 x + 28

3 z^{2} - 8 z + 4 = 5 z

\frac{y ^{2}}{4} = \frac{3 y + 4}{4}

What are the solutions to the equation (2x-3)^2-8=0 ?
The solutions to the equation (2x-3)^2-8=0 are x=(2sqrt(2)+3)/2 ,x=(-2sqrt(2)+3)/2
Find the zeros of (2x-3)^2-8=0
The zeros of (2x-3)^2-8=0 are x=(2sqrt(2)+3)/2 ,x=(-2sqrt(2)+3)/2