What are the solutions to the equation 8x^2+2x=7x ?

The solutions to the equation 8x^2+2x=7x are x= 5/8 ,x=0

Find the zeros of 8x^2+2x=7x

The zeros of 8x^2+2x=7x are x= 5/8 ,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 x^{2} + 2 x = 7 x

x = \frac{5}{8}, x = 0

Decimal Notation

x = 0.625, x = 0

Solution steps

8 x^{2} + 2 x = 7 x

Move

7 x

to the left side

8 x^{2} - 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

(- 5)^{2} - 4 \cdot 8 \cdot 0 = 5

x_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 8}, x_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 8}

x = \frac{- ( - 5 ) + 5}{2 \cdot 8} : \frac{5}{8}

x = \frac{- ( - 5 ) - 5}{2 \cdot 8} : 0

The solutions to the quadratic equation are:

x = \frac{5}{8}, x = 0

(x - 6) (x - 3) = 4

(6 - x)^{2} - 1 = 0

x, x^{2} + 2 x y = 0

x, t x^{2} - 12 x + 9 = 0

(2 x + 1)^{2} = 1

What are the solutions to the equation 8x^2+2x=7x ?
The solutions to the equation 8x^2+2x=7x are x= 5/8 ,x=0
Find the zeros of 8x^2+2x=7x
The zeros of 8x^2+2x=7x are x= 5/8 ,x=0