What are the solutions to the equation solvefor x,x^2+2xy=0 ?

The solutions to the equation solvefor x,x^2+2xy=0 are x=0,x=-2y

Find the zeros of solvefor x,x^2+2xy=0

The zeros of solvefor x,x^2+2xy=0 are x=0,x=-2y

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solve for

x, x^{2} + 2 x y = 0

x = 0, x = - 2 y

Solution steps

x^{2} + 2 x y = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 y x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 y \pm ( 2 y ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

Simplify

(2 y)^{2} - 4 \cdot 1 \cdot 0 : 2 y

x_{1, 2} = \frac{- 2 y \pm 2 y}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 y + 2 y}{2 \cdot 1}, x_{2} = \frac{- 2 y - 2 y}{2 \cdot 1}

x = \frac{- 2 y + 2 y}{2 \cdot 1} : 0

x = \frac{- 2 y - 2 y}{2 \cdot 1} : - 2 y

The solutions to the quadratic equation are:

x = 0, x = - 2 y

x, t x^{2} - 12 x + 9 = 0

(2 x + 1)^{2} = 1

4 (5 x - 2)^{2} - 9 = 4

x^{2} - x - 0.2 = 0

2 x^{2} - 20 x = 14

What are the solutions to the equation solvefor x,x^2+2xy=0 ?
The solutions to the equation solvefor x,x^2+2xy=0 are x=0,x=-2y
Find the zeros of solvefor x,x^2+2xy=0
The zeros of solvefor x,x^2+2xy=0 are x=0,x=-2y