What are the solutions to the equation 2x^2-20x=14 ?

The solutions to the equation 2x^2-20x=14 are x=5+4sqrt(2),x=5-4sqrt(2)

Find the zeros of 2x^2-20x=14

The zeros of 2x^2-20x=14 are x=5+4sqrt(2),x=5-4sqrt(2)

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2 x^{2} - 20 x = 14

x = 5 + 42, x = 5 - 42

Decimal Notation

x = 10.65685 \dots, x = - 0.65685 \dots

Solution steps

2 x^{2} - 20 x = 14

Move

14

to the left side

2 x^{2} - 20 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 2 ( - 14 )}{2 \cdot 2}

(- 20)^{2} - 4 \cdot 2 (- 14) = 162

x_{1, 2} = \frac{- ( - 20 ) \pm 16 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 16 2}{2 \cdot 2}, x_{2} = \frac{- ( - 20 ) - 16 2}{2 \cdot 2}

x = \frac{- ( - 20 ) + 16 2}{2 \cdot 2} : 5 + 42

x = \frac{- ( - 20 ) - 16 2}{2 \cdot 2} : 5 - 42

The solutions to the quadratic equation are:

x = 5 + 42, x = 5 - 42

v^{2} = 12 v - 25

5 t^{2} - 21 t + 11 = - 4 t

3 x^{2} + 6 x - 8 = 4 x

2 z^{2} - 2 z - 12 = 0

3 t^{2} - t - 6 = 0

What are the solutions to the equation 2x^2-20x=14 ?
The solutions to the equation 2x^2-20x=14 are x=5+4sqrt(2),x=5-4sqrt(2)
Find the zeros of 2x^2-20x=14
The zeros of 2x^2-20x=14 are x=5+4sqrt(2),x=5-4sqrt(2)