What are the solutions to the equation completesquare 3t^2-t-6=0 ?

The solutions to the equation completesquare 3t^2-t-6=0 are t=(sqrt(73)+1)/6 ,t=(-sqrt(73)+1)/6

Find the zeros of completesquare 3t^2-t-6=0

The zeros of completesquare 3t^2-t-6=0 are t=(sqrt(73)+1)/6 ,t=(-sqrt(73)+1)/6

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3 t^{2} - t - 6 = 0

t = \frac{73 + 1}{6}, t = \frac{- 73 + 1}{6}

Decimal Notation

t = 1.59066 \dots, t = - 1.25733 \dots

Solution steps

3 t^{2} - t - 6 = 0

Move

6

to the right side

3 t^{2} - t = 6

Divide both sides by

3

\frac{3 t ^{2} - t}{3} = \frac{6}{3}

t^{2} - \frac{t}{3} = 2

Rewrite in the form

(x + a)^{2} = b

(t - \frac{1}{6})^{2} = \frac{73}{36}

For

the solutions are

f (x) = a, - a

Solve

t - \frac{1}{6} = \frac{73}{36} : t = \frac{73 + 1}{6}

Solve

t - \frac{1}{6} = - \frac{73}{36} : t = \frac{- 73 + 1}{6}

The solutions to the quadratic equation are:

t = \frac{73 + 1}{6}, t = \frac{- 73 + 1}{6}

x \cdot x - x = 12

2 x^{2} - 20 + 46 = 0

5 x^{2} - 2 = 38

6 x^{2} = 5 x - 1

(x + 1) (x - 1) = 2 (x + 5)

What are the solutions to the equation completesquare 3t^2-t-6=0 ?
The solutions to the equation completesquare 3t^2-t-6=0 are t=(sqrt(73)+1)/6 ,t=(-sqrt(73)+1)/6
Find the zeros of completesquare 3t^2-t-6=0
The zeros of completesquare 3t^2-t-6=0 are t=(sqrt(73)+1)/6 ,t=(-sqrt(73)+1)/6