What are the solutions to the equation -4z^2+13z-3=0 ?

The solutions to the equation -4z^2+13z-3=0 are z= 1/4 ,z=3

Find the zeros of -4z^2+13z-3=0

The zeros of -4z^2+13z-3=0 are z= 1/4 ,z=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 4 z^{2} + 13 z - 3 = 0

z = \frac{1}{4}, z = 3

Decimal Notation

z = 0.25, z = 3

Solution steps

- 4 z^{2} + 13 z - 3 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 ( - 4 ) ( - 3 )}{2 ( - 4 )}

1 3^{2} - 4 (- 4) (- 3) = 11

z_{1, 2} = \frac{- 13 \pm 11}{2 ( - 4 )}

Separate the solutions

z_{1} = \frac{- 13 + 11}{2 ( - 4 )}, z_{2} = \frac{- 13 - 11}{2 ( - 4 )}

z = \frac{- 13 + 11}{2 ( - 4 )} : \frac{1}{4}

z = \frac{- 13 - 11}{2 ( - 4 )} : 3

The solutions to the quadratic equation are:

z = \frac{1}{4}, z = 3

u^{2} + 13 u + 36 = 0

- 2 x + 1 = - x^{2} + 4

4 - x^{2} = 2 + x

x^{2} + \frac{x}{2} = 5

6 x^{2} - 8 x = 3 x - 4

What are the solutions to the equation -4z^2+13z-3=0 ?
The solutions to the equation -4z^2+13z-3=0 are z= 1/4 ,z=3
Find the zeros of -4z^2+13z-3=0
The zeros of -4z^2+13z-3=0 are z= 1/4 ,z=3