What are the solutions to the equation x^2+x/2 =5 ?

The solutions to the equation x^2+x/2 =5 are x=2,x=-5/2

Find the zeros of x^2+x/2 =5

The zeros of x^2+x/2 =5 are x=2,x=-5/2

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x^{2} + \frac{x}{2} = 5

x = 2, x = - \frac{5}{2}

Decimal Notation

x = 2, x = - 2.5

Solution steps

x^{2} + \frac{x}{2} = 5

Multiply both sides by

2

2 x^{2} + x = 10

Move

10

to the left side

2 x^{2} + x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 10) = 9

x_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 9}{2 \cdot 2}, x_{2} = \frac{- 1 - 9}{2 \cdot 2}

x = \frac{- 1 + 9}{2 \cdot 2} : 2

x = \frac{- 1 - 9}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{5}{2}

6 x^{2} - 8 x = 3 x - 4

4 x^{2} + 3 x = 24 - x

5 t = t^{2}

\frac{x ^{2}}{3} - 192 = 0

3 x^{2} = 14

What are the solutions to the equation x^2+x/2 =5 ?
The solutions to the equation x^2+x/2 =5 are x=2,x=-5/2
Find the zeros of x^2+x/2 =5
The zeros of x^2+x/2 =5 are x=2,x=-5/2