What are the solutions to the equation 5t=t^2 ?

The solutions to the equation 5t=t^2 are t=5,t=0

Find the zeros of 5t=t^2

The zeros of 5t=t^2 are t=5,t=0

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5 t = t^{2}

t = 5, t = 0

Solution steps

5 t = t^{2}

Switch sides

t^{2} = 5 t

Move

5 t

to the left side

t^{2} - 5 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 0 = 5

t_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 1}, t_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 1}

t = \frac{- ( - 5 ) + 5}{2 \cdot 1} : 5

t = \frac{- ( - 5 ) - 5}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

t = 5, t = 0

\frac{x ^{2}}{3} - 192 = 0

3 x^{2} = 14

x^{2} = x - x^{2}

4 a^{2} + 19 a + 12 = - 5

3 (x - 4) (2 x - 3) = 0

What are the solutions to the equation 5t=t^2 ?
The solutions to the equation 5t=t^2 are t=5,t=0
Find the zeros of 5t=t^2
The zeros of 5t=t^2 are t=5,t=0