What are the solutions to the equation 4a^2+19a+12=-5 ?

The solutions to the equation 4a^2+19a+12=-5 are a=(-19+sqrt(89))/8 ,a=(-19-sqrt(89))/8

Find the zeros of 4a^2+19a+12=-5

The zeros of 4a^2+19a+12=-5 are a=(-19+sqrt(89))/8 ,a=(-19-sqrt(89))/8

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4 a^{2} + 19 a + 12 = - 5

a = \frac{- 19 + 89}{8}, a = \frac{- 19 - 89}{8}

Decimal Notation

a = - 1.19575 \dots, a = - 3.55424 \dots

Solution steps

4 a^{2} + 19 a + 12 = - 5

Move

5

to the left side

4 a^{2} + 19 a + 17 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 4 \cdot 17}{2 \cdot 4}

1 9^{2} - 4 \cdot 4 \cdot 17 = 89

a_{1, 2} = \frac{- 19 \pm 89}{2 \cdot 4}

Separate the solutions

a_{1} = \frac{- 19 + 89}{2 \cdot 4}, a_{2} = \frac{- 19 - 89}{2 \cdot 4}

a = \frac{- 19 + 89}{2 \cdot 4} : \frac{- 19 + 89}{8}

a = \frac{- 19 - 89}{2 \cdot 4} : \frac{- 19 - 89}{8}

The solutions to the quadratic equation are:

a = \frac{- 19 + 89}{8}, a = \frac{- 19 - 89}{8}

3 (x - 4) (2 x - 3) = 0

50 - \frac{x ^{2}}{2} = 26 + x

x^{2} + 7 - 8 = 0

12 x^{2} = 60 x

y = 4 x - x^{2}, x

What are the solutions to the equation 4a^2+19a+12=-5 ?
The solutions to the equation 4a^2+19a+12=-5 are a=(-19+sqrt(89))/8 ,a=(-19-sqrt(89))/8
Find the zeros of 4a^2+19a+12=-5
The zeros of 4a^2+19a+12=-5 are a=(-19+sqrt(89))/8 ,a=(-19-sqrt(89))/8