What are the solutions to the equation 6r^2-48r-54=0 ?

The solutions to the equation 6r^2-48r-54=0 are r=9,r=-1

Find the zeros of 6r^2-48r-54=0

The zeros of 6r^2-48r-54=0 are r=9,r=-1

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6 r^{2} - 48 r - 54 = 0

r = 9, r = - 1

Solution steps

6 r^{2} - 48 r - 54 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 6 ( - 54 )}{2 \cdot 6}

(- 48)^{2} - 4 \cdot 6 (- 54) = 60

r_{1, 2} = \frac{- ( - 48 ) \pm 60}{2 \cdot 6}

Separate the solutions

r_{1} = \frac{- ( - 48 ) + 60}{2 \cdot 6}, r_{2} = \frac{- ( - 48 ) - 60}{2 \cdot 6}

r = \frac{- ( - 48 ) + 60}{2 \cdot 6} : 9

r = \frac{- ( - 48 ) - 60}{2 \cdot 6} : - 1

The solutions to the quadratic equation are:

r = 9, r = - 1

x, x^{2} + y^{2} = 25

\frac{2}{3} x^{2} + 15 = 23

L (v) = 2 v^{2} + 50 v + 10

2 x^{2} + 16 x - 24 = 0

t, f n (t) = 5 t - t^{2}

What are the solutions to the equation 6r^2-48r-54=0 ?
The solutions to the equation 6r^2-48r-54=0 are r=9,r=-1
Find the zeros of 6r^2-48r-54=0
The zeros of 6r^2-48r-54=0 are r=9,r=-1