What are the solutions to the equation 10x^2+25x=0 ?

The solutions to the equation 10x^2+25x=0 are x=0,x=-5/2

Find the zeros of 10x^2+25x=0

The zeros of 10x^2+25x=0 are x=0,x=-5/2

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10 x^{2} + 25 x = 0

x = 0, x = - \frac{5}{2}

Decimal Notation

x = 0, x = - 2.5

Solution steps

10 x^{2} + 25 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 10 \cdot 0}{2 \cdot 10}

2 5^{2} - 4 \cdot 10 \cdot 0 = 25

x_{1, 2} = \frac{- 25 \pm 25}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 25 + 25}{2 \cdot 10}, x_{2} = \frac{- 25 - 25}{2 \cdot 10}

x = \frac{- 25 + 25}{2 \cdot 10} : 0

x = \frac{- 25 - 25}{2 \cdot 10} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{5}{2}

x, F = (m - 2) x^{2} + (n - 1) x + (p - 3)

(x + 9)^{2} = 12

x, x^{2} + 4 x - 2 a y + 2 (2 - a^{2}) = 0

3 x^{2} + 10 x + 12 = 4

7 x^{2} = 23 x

What are the solutions to the equation 10x^2+25x=0 ?
The solutions to the equation 10x^2+25x=0 are x=0,x=-5/2
Find the zeros of 10x^2+25x=0
The zeros of 10x^2+25x=0 are x=0,x=-5/2