What are the solutions to the equation x(-2x-11)=-3 ?

The solutions to the equation x(-2x-11)=-3 are x=-(11+sqrt(145))/4 ,x=(sqrt(145)-11)/4

Find the zeros of x(-2x-11)=-3

The zeros of x(-2x-11)=-3 are x=-(11+sqrt(145))/4 ,x=(sqrt(145)-11)/4

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x (- 2 x - 11) = - 3

x = - \frac{11 + 145}{4}, x = \frac{145 - 11}{4}

Decimal Notation

x = - 5.76039 \dots, x = 0.26039 \dots

Solution steps

x (- 2 x - 11) = - 3

Expand

x (- 2 x - 11) : - 2 x^{2} - 11 x

- 2 x^{2} - 11 x = - 3

Move

3

to the left side

- 2 x^{2} - 11 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 ( - 2 ) \cdot 3}{2 ( - 2 )}

(- 11)^{2} - 4 (- 2) \cdot 3 = 145

x_{1, 2} = \frac{- ( - 11 ) \pm 145}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 145}{2 ( - 2 )}, x_{2} = \frac{- ( - 11 ) - 145}{2 ( - 2 )}

x = \frac{- ( - 11 ) + 145}{2 ( - 2 )} : - \frac{11 + 145}{4}

x = \frac{- ( - 11 ) - 145}{2 ( - 2 )} : \frac{145 - 11}{4}

The solutions to the quadratic equation are:

x = - \frac{11 + 145}{4}, x = \frac{145 - 11}{4}

y^{2} + 6 y = 16

3 7^{2} = 3 5^{2} + x^{2}

6 x^{2} - 3 x = 0

5 x^{2} - 10 x = 0

(x + 31)^{2} - 361 = 0

What are the solutions to the equation x(-2x-11)=-3 ?
The solutions to the equation x(-2x-11)=-3 are x=-(11+sqrt(145))/4 ,x=(sqrt(145)-11)/4
Find the zeros of x(-2x-11)=-3
The zeros of x(-2x-11)=-3 are x=-(11+sqrt(145))/4 ,x=(sqrt(145)-11)/4