What are the solutions to the equation y^2+6y=16 ?

The solutions to the equation y^2+6y=16 are y=2,y=-8

Find the zeros of y^2+6y=16

The zeros of y^2+6y=16 are y=2,y=-8

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y^{2} + 6 y = 16

y = 2, y = - 8

Solution steps

y^{2} + 6 y = 16

Move

16

to the left side

y^{2} + 6 y - 16 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 16) = 10

y_{1, 2} = \frac{- 6 \pm 10}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 6 + 10}{2 \cdot 1}, y_{2} = \frac{- 6 - 10}{2 \cdot 1}

y = \frac{- 6 + 10}{2 \cdot 1} : 2

y = \frac{- 6 - 10}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

y = 2, y = - 8

3 7^{2} = 3 5^{2} + x^{2}

6 x^{2} - 3 x = 0

5 x^{2} - 10 x = 0

(x + 31)^{2} - 361 = 0

\frac{1}{2} x^{2} + 2 x + 6 = 0

What are the solutions to the equation y^2+6y=16 ?
The solutions to the equation y^2+6y=16 are y=2,y=-8
Find the zeros of y^2+6y=16
The zeros of y^2+6y=16 are y=2,y=-8