What are the solutions to the equation 1/2 x^2+2x+6=0 ?

The solutions to the equation 1/2 x^2+2x+6=0 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i

Find the zeros of 1/2 x^2+2x+6=0

The zeros of 1/2 x^2+2x+6=0 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{1}{2} x^{2} + 2 x + 6 = 0

x = - 2 + 22 i, x = - 2 - 22 i

Solution steps

\frac{1}{2} x^{2} + 2 x + 6 = 0

Multiply both sides by

2

x^{2} + 4 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 12 : 42 i

x_{1, 2} = \frac{- 4 \pm 4 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4 2 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 4 2 i}{2 \cdot 1}

x = \frac{- 4 + 4 2 i}{2 \cdot 1} : - 2 + 22 i

x = \frac{- 4 - 4 2 i}{2 \cdot 1} : - 2 - 22 i

The solutions to the quadratic equation are:

x = - 2 + 22 i, x = - 2 - 22 i

9 x^{2} = 5 x

(4 m - 1) (m + 5) = 0

4 (x^{2} + x - 2) = x - x^{2} - 7

175 = - 0.01 q^{2} + 200

4 = x (x + 3)

What are the solutions to the equation 1/2 x^2+2x+6=0 ?
The solutions to the equation 1/2 x^2+2x+6=0 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i
Find the zeros of 1/2 x^2+2x+6=0
The zeros of 1/2 x^2+2x+6=0 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i