What are the solutions to the equation (4m-1)(m+5)=0 ?

The solutions to the equation (4m-1)(m+5)=0 are m= 1/4 ,m=-5

Find the zeros of (4m-1)(m+5)=0

The zeros of (4m-1)(m+5)=0 are m= 1/4 ,m=-5

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(4 m - 1) (m + 5) = 0

m = \frac{1}{4}, m = - 5

Decimal Notation

m = 0.25, m = - 5

Solution steps

(4 m - 1) (m + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 m - 1 = 0 or m + 5 = 0

Solve

4 m - 1 = 0 : m = \frac{1}{4}

Solve

m + 5 = 0 : m = - 5

The solutions to the quadratic equation are:

m = \frac{1}{4}, m = - 5

4 (x^{2} + x - 2) = x - x^{2} - 7

175 = - 0.01 q^{2} + 200

4 = x (x + 3)

a = \frac{1}{2} π r^{2}

(5 x + n)^{2} - 4 = 0

What are the solutions to the equation (4m-1)(m+5)=0 ?
The solutions to the equation (4m-1)(m+5)=0 are m= 1/4 ,m=-5
Find the zeros of (4m-1)(m+5)=0
The zeros of (4m-1)(m+5)=0 are m= 1/4 ,m=-5