What are the solutions to the equation 10q^2-4q+1=6q^2 ?

The solutions to the equation 10q^2-4q+1=6q^2 are q= 1/2

Find the zeros of 10q^2-4q+1=6q^2

The zeros of 10q^2-4q+1=6q^2 are q= 1/2

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10 q^{2} - 4 q + 1 = 6 q^{2}

q = \frac{1}{2}

Decimal Notation

q = 0.5

Solution steps

10 q^{2} - 4 q + 1 = 6 q^{2}

Move

6 q^{2}

to the left side

4 q^{2} - 4 q + 1 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

q_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

q = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

q = \frac{1}{2}

The solution to the quadratic equation is:

q = \frac{1}{2}

x, x^{2} = y^{2} + 4 z^{2}

2 x^{2} + 12 x = - 3

8 x^{2} + 13 x - 6 = 0

x, y = x^{2} - 4 x

(x - 7)^{2} = 15

What are the solutions to the equation 10q^2-4q+1=6q^2 ?
The solutions to the equation 10q^2-4q+1=6q^2 are q= 1/2
Find the zeros of 10q^2-4q+1=6q^2
The zeros of 10q^2-4q+1=6q^2 are q= 1/2