What are the solutions to the equation 20x+100=400-x^2 ?

The solutions to the equation 20x+100=400-x^2 are x=-30,x=10

Find the zeros of 20x+100=400-x^2

The zeros of 20x+100=400-x^2 are x=-30,x=10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

20 x + 100 = 400 - x^{2}

x = - 30, x = 10

Solution steps

20 x + 100 = 400 - x^{2}

Switch sides

400 - x^{2} = 20 x + 100

Move

100

to the left side

- x^{2} + 300 = 20 x

Move

20 x

to the left side

- x^{2} + 300 - 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - 20 x + 300 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 ( - 1 ) \cdot 300}{2 ( - 1 )}

(- 20)^{2} - 4 (- 1) \cdot 300 = 40

x_{1, 2} = \frac{- ( - 20 ) \pm 40}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 40}{2 ( - 1 )}, x_{2} = \frac{- ( - 20 ) - 40}{2 ( - 1 )}

x = \frac{- ( - 20 ) + 40}{2 ( - 1 )} : - 30

x = \frac{- ( - 20 ) - 40}{2 ( - 1 )} : 10

The solutions to the quadratic equation are:

x = - 30, x = 10

- 4 x^{2} + 8 x + 12 = 0

4 p^{2} + p - 6 = 0

3 x^{2} + 16 x + 1 = 9 x - 3

- 6 x^{2} = - 24

9 k^{2} - 18 k + 5 = 0

What are the solutions to the equation 20x+100=400-x^2 ?
The solutions to the equation 20x+100=400-x^2 are x=-30,x=10
Find the zeros of 20x+100=400-x^2
The zeros of 20x+100=400-x^2 are x=-30,x=10