What are the solutions to the equation 2x^2-4x-10=-4 ?

The solutions to the equation 2x^2-4x-10=-4 are x=3,x=-1

Find the zeros of 2x^2-4x-10=-4

The zeros of 2x^2-4x-10=-4 are x=3,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 4 x - 10 = - 4

x = 3, x = - 1

Solution steps

2 x^{2} - 4 x - 10 = - 4

Move

4

to the left side

2 x^{2} - 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 6) = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 2}

x = \frac{- ( - 4 ) + 8}{2 \cdot 2} : 3

x = \frac{- ( - 4 ) - 8}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = 3, x = - 1

64 = 16 t^{2}

x^{2} + 9 x + 20 = - 3 x

3 x^{2} + 2 x - e = 0

3 x^{2} + 9 x + 2 = 4

10 b^{2} - 15 b = 8 b - 12

What are the solutions to the equation 2x^2-4x-10=-4 ?
The solutions to the equation 2x^2-4x-10=-4 are x=3,x=-1
Find the zeros of 2x^2-4x-10=-4
The zeros of 2x^2-4x-10=-4 are x=3,x=-1