What are the solutions to the equation 6x^2-12x+3=0 ?

The solutions to the equation 6x^2-12x+3=0 are x=(2+sqrt(2))/2 ,x=(2-sqrt(2))/2

Find the zeros of 6x^2-12x+3=0

The zeros of 6x^2-12x+3=0 are x=(2+sqrt(2))/2 ,x=(2-sqrt(2))/2

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6 x^{2} - 12 x + 3 = 0

x = \frac{2 + 2}{2}, x = \frac{2 - 2}{2}

Decimal Notation

x = 1.70710 \dots, x = 0.29289 \dots

Solution steps

6 x^{2} - 12 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 6 \cdot 3}{2 \cdot 6}

(- 12)^{2} - 4 \cdot 6 \cdot 3 = 62

x_{1, 2} = \frac{- ( - 12 ) \pm 6 2}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 2}{2 \cdot 6}, x_{2} = \frac{- ( - 12 ) - 6 2}{2 \cdot 6}

x = \frac{- ( - 12 ) + 6 2}{2 \cdot 6} : \frac{2 + 2}{2}

x = \frac{- ( - 12 ) - 6 2}{2 \cdot 6} : \frac{2 - 2}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 2}{2}, x = \frac{2 - 2}{2}

y^{2} = 13 y - 42

x^{2} + 20 x - 96 = 0

9 x^{2} + 12 x + 5 = 10

v, p^{1} v^{1} = p^{2} v^{2}

3 x^{2} - 5 x = 0

What are the solutions to the equation 6x^2-12x+3=0 ?
The solutions to the equation 6x^2-12x+3=0 are x=(2+sqrt(2))/2 ,x=(2-sqrt(2))/2
Find the zeros of 6x^2-12x+3=0
The zeros of 6x^2-12x+3=0 are x=(2+sqrt(2))/2 ,x=(2-sqrt(2))/2