What are the solutions to the equation 3800=x^2-160x+10000 ?

The solutions to the equation 3800=x^2-160x+10000 are x=10(8+sqrt(2)),x=10(8-sqrt(2))

Find the zeros of 3800=x^2-160x+10000

The zeros of 3800=x^2-160x+10000 are x=10(8+sqrt(2)),x=10(8-sqrt(2))

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3800 = x^{2} - 160 x + 10000

x = 10 (8 + 2), x = 10 (8 - 2)

Decimal Notation

x = 94.14213 \dots, x = 65.85786 \dots

Solution steps

3800 = x^{2} - 160 x + 10000

Switch sides

x^{2} - 160 x + 10000 = 3800

Move

3800

to the left side

x^{2} - 160 x + 6200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 160 ) \pm ( - 160 ) ^{2} - 4 \cdot 1 \cdot 6200}{2 \cdot 1}

(- 160)^{2} - 4 \cdot 1 \cdot 6200 = 202

x_{1, 2} = \frac{- ( - 160 ) \pm 20 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 160 ) + 20 2}{2 \cdot 1}, x_{2} = \frac{- ( - 160 ) - 20 2}{2 \cdot 1}

x = \frac{- ( - 160 ) + 20 2}{2 \cdot 1} : 10 (8 + 2)

x = \frac{- ( - 160 ) - 20 2}{2 \cdot 1} : 10 (8 - 2)

The solutions to the quadratic equation are:

x = 10 (8 + 2), x = 10 (8 - 2)

x^{2} + 16 x + 88 = 0

(2 x + 3)^{2} = 117 - x^{2}

2 x^{2} + (x - 15)^{2} = 4 x + 185

x^{2} + 24 x + 140 = 0

15 x^{2} + 12 = - 8 x

What are the solutions to the equation 3800=x^2-160x+10000 ?
The solutions to the equation 3800=x^2-160x+10000 are x=10(8+sqrt(2)),x=10(8-sqrt(2))
Find the zeros of 3800=x^2-160x+10000
The zeros of 3800=x^2-160x+10000 are x=10(8+sqrt(2)),x=10(8-sqrt(2))