What are the solutions to the equation (x+7)(x+3)=21 ?

The solutions to the equation (x+7)(x+3)=21 are x=0,x=-10

Find the zeros of (x+7)(x+3)=21

The zeros of (x+7)(x+3)=21 are x=0,x=-10

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(x + 7) (x + 3) = 21

x = 0, x = - 10

Solution steps

(x + 7) (x + 3) = 21

Expand

(x + 7) (x + 3) : x^{2} + 10 x + 21

x^{2} + 10 x + 21 = 21

Move

21

to the left side

x^{2} + 10 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 0 = 10

x_{1, 2} = \frac{- 10 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 10}{2 \cdot 1}, x_{2} = \frac{- 10 - 10}{2 \cdot 1}

x = \frac{- 10 + 10}{2 \cdot 1} : 0

x = \frac{- 10 - 10}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 0, x = - 10

2 x^{2} + 2 = 4 x - 2

6 q^{2} - 18 q + 12 = 0

x (x + 1) = 342

9 x^{2} = - 9 x

x^{2} - 10 x + 63 = 6 x

What are the solutions to the equation (x+7)(x+3)=21 ?
The solutions to the equation (x+7)(x+3)=21 are x=0,x=-10
Find the zeros of (x+7)(x+3)=21
The zeros of (x+7)(x+3)=21 are x=0,x=-10