What are the solutions to the equation x^2-10x+63=6x ?

The solutions to the equation x^2-10x+63=6x are x=9,x=7

Find the zeros of x^2-10x+63=6x

The zeros of x^2-10x+63=6x are x=9,x=7

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x^{2} - 10 x + 63 = 6 x

x = 9, x = 7

Solution steps

x^{2} - 10 x + 63 = 6 x

Move

6 x

to the left side

x^{2} - 16 x + 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 63}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 63 = 2

x_{1, 2} = \frac{- ( - 16 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 2}{2 \cdot 1}

x = \frac{- ( - 16 ) + 2}{2 \cdot 1} : 9

x = \frac{- ( - 16 ) - 2}{2 \cdot 1} : 7

The solutions to the quadratic equation are:

x = 9, x = 7

5 x^{2} + 5 x - 3 = - 8 x - 9

x^{2} - 13 x + 40 = 0

y, \frac{X ^{2}}{a ^{2}} - \frac{y ^{2}}{b ^{2}} = 1

x^{2} - 10 x + 25 = 2

6 x^{2} - 29 x - 5 = 0

What are the solutions to the equation x^2-10x+63=6x ?
The solutions to the equation x^2-10x+63=6x are x=9,x=7
Find the zeros of x^2-10x+63=6x
The zeros of x^2-10x+63=6x are x=9,x=7