What are the solutions to the equation 2x^2+26=12x ?

The solutions to the equation 2x^2+26=12x are x=3+2i,x=3-2i

Find the zeros of 2x^2+26=12x

The zeros of 2x^2+26=12x are x=3+2i,x=3-2i

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2 x^{2} + 26 = 12 x

x = 3 + 2 i, x = 3 - 2 i

Solution steps

2 x^{2} + 26 = 12 x

Move

12 x

to the left side

2 x^{2} + 26 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 12 x + 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 \cdot 26}{2 \cdot 2}

Simplify

(- 12)^{2} - 4 \cdot 2 \cdot 26 : 8 i

x_{1, 2} = \frac{- ( - 12 ) \pm 8 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 8 i}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 8 i}{2 \cdot 2}

x = \frac{- ( - 12 ) + 8 i}{2 \cdot 2} : 3 + 2 i

x = \frac{- ( - 12 ) - 8 i}{2 \cdot 2} : 3 - 2 i

The solutions to the quadratic equation are:

x = 3 + 2 i, x = 3 - 2 i

\frac{x ^{2}}{3} - x = \frac{5}{6}

x^{2} - 19 x + 32 = 0

2 x^{2} + 8 x - 9 = 0

x^{2} - 14 x + 16 = 0

11 n^{2} + 3 = - 12 n

What are the solutions to the equation 2x^2+26=12x ?
The solutions to the equation 2x^2+26=12x are x=3+2i,x=3-2i
Find the zeros of 2x^2+26=12x
The zeros of 2x^2+26=12x are x=3+2i,x=3-2i