What are the solutions to the equation 2x^2+8x-9=0 ?

The solutions to the equation 2x^2+8x-9=0 are x=(-4+sqrt(34))/2 ,x=-(4+sqrt(34))/2

Find the zeros of 2x^2+8x-9=0

The zeros of 2x^2+8x-9=0 are x=(-4+sqrt(34))/2 ,x=-(4+sqrt(34))/2

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2 x^{2} + 8 x - 9 = 0

x = \frac{- 4 + 34}{2}, x = - \frac{4 + 34}{2}

Decimal Notation

x = 0.91547 \dots, x = - 4.91547 \dots

Solution steps

2 x^{2} + 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 9) = 234

x_{1, 2} = \frac{- 8 \pm 2 34}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 2 34}{2 \cdot 2}, x_{2} = \frac{- 8 - 2 34}{2 \cdot 2}

x = \frac{- 8 + 2 34}{2 \cdot 2} : \frac{- 4 + 34}{2}

x = \frac{- 8 - 2 34}{2 \cdot 2} : - \frac{4 + 34}{2}

The solutions to the quadratic equation are:

x = \frac{- 4 + 34}{2}, x = - \frac{4 + 34}{2}

x^{2} - 14 x + 16 = 0

11 n^{2} + 3 = - 12 n

x, f = - x^{2} + (k + 4) x - 5

y^{2} - 14 y = - 26

x, x^{2} + 4 x + y^{2} - 6 y + z = - 8

What are the solutions to the equation 2x^2+8x-9=0 ?
The solutions to the equation 2x^2+8x-9=0 are x=(-4+sqrt(34))/2 ,x=-(4+sqrt(34))/2
Find the zeros of 2x^2+8x-9=0
The zeros of 2x^2+8x-9=0 are x=(-4+sqrt(34))/2 ,x=-(4+sqrt(34))/2