What are the solutions to the equation -7x^2+6x+3=0 ?

The solutions to the equation -7x^2+6x+3=0 are x=-(-3+sqrt(30))/7 ,x=(3+sqrt(30))/7

Find the zeros of -7x^2+6x+3=0

The zeros of -7x^2+6x+3=0 are x=-(-3+sqrt(30))/7 ,x=(3+sqrt(30))/7

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- 7 x^{2} + 6 x + 3 = 0

x = - \frac{- 3 + 30}{7}, x = \frac{3 + 30}{7}

Decimal Notation

x = - 0.35388 \dots, x = 1.21103 \dots

Solution steps

- 7 x^{2} + 6 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 7 ) \cdot 3}{2 ( - 7 )}

6^{2} - 4 (- 7) \cdot 3 = 230

x_{1, 2} = \frac{- 6 \pm 2 30}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 30}{2 ( - 7 )}, x_{2} = \frac{- 6 - 2 30}{2 ( - 7 )}

x = \frac{- 6 + 2 30}{2 ( - 7 )} : - \frac{- 3 + 30}{7}

x = \frac{- 6 - 2 30}{2 ( - 7 )} : \frac{3 + 30}{7}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 30}{7}, x = \frac{3 + 30}{7}

6 x = 27 - x^{2}

(x + 5) (x - 2) = - 12

12 + 0.3 q = 111 - 0.1 q^{2}

x, 3 x^{2} y = x + 9

x, y = 9 - x^{2}

What are the solutions to the equation -7x^2+6x+3=0 ?
The solutions to the equation -7x^2+6x+3=0 are x=-(-3+sqrt(30))/7 ,x=(3+sqrt(30))/7
Find the zeros of -7x^2+6x+3=0
The zeros of -7x^2+6x+3=0 are x=-(-3+sqrt(30))/7 ,x=(3+sqrt(30))/7