What are the solutions to the equation -2(x+3)(7x+5)=0 ?

The solutions to the equation -2(x+3)(7x+5)=0 are x=-3,x=-5/7

Find the zeros of -2(x+3)(7x+5)=0

The zeros of -2(x+3)(7x+5)=0 are x=-3,x=-5/7

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- 2 (x + 3) (7 x + 5) = 0

x = - 3, x = - \frac{5}{7}

Decimal Notation

x = - 3, x = - 0.71428 \dots

Solution steps

- 2 (x + 3) (7 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or 7 x + 5 = 0

Solve

x + 3 = 0 : x = - 3

Solve

7 x + 5 = 0 : x = - \frac{5}{7}

The solutions to the quadratic equation are:

x = - 3, x = - \frac{5}{7}

x^{2} + 5 x - 300 = 0

1927.8 = 0.68 \cdot 2.14 \cdot 100 \cdot x \cdot (9.5 - 0.4 \cdot x)

(X + 3)^{2} - (X - 1)^{2} = X^{2}

2 x^{2} - 8 x + 8 = 0

15 x^{2} - 38 x - 32 = 0

What are the solutions to the equation -2(x+3)(7x+5)=0 ?
The solutions to the equation -2(x+3)(7x+5)=0 are x=-3,x=-5/7
Find the zeros of -2(x+3)(7x+5)=0
The zeros of -2(x+3)(7x+5)=0 are x=-3,x=-5/7