What are the solutions to the equation factor x^2-12x+32=0 ?

The solutions to the equation factor x^2-12x+32=0 are x=4,x=8

Find the zeros of factor x^2-12x+32=0

The zeros of factor x^2-12x+32=0 are x=4,x=8

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x^{2} - 12 x + 32 = 0

x = 4, x = 8

Solution steps

x^{2} - 12 x + 32 = 0

Factor

x^{2} - 12 x + 32 : (x - 4) (x - 8)

(x - 4) (x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x - 8 = 0

Solve

x - 4 = 0 : x = 4

Solve

x - 8 = 0 : x = 8

The solutions to the quadratic equation are:

x = 4, x = 8

(3 x - \frac{1}{4})^{2} = \frac{9}{25}

n^{2} - n - 306 = 0

4 x^{2} + 4 x + 10

0.2 x^{2} + 0.6 x = x

3 x^{2} - 2 x - 1 = 0

What are the solutions to the equation factor x^2-12x+32=0 ?
The solutions to the equation factor x^2-12x+32=0 are x=4,x=8
Find the zeros of factor x^2-12x+32=0
The zeros of factor x^2-12x+32=0 are x=4,x=8