What are the solutions to the equation 0.2x^2+0.6x=x ?

The solutions to the equation 0.2x^2+0.6x=x are x=2,x=0

Find the zeros of 0.2x^2+0.6x=x

The zeros of 0.2x^2+0.6x=x are x=2,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0.2 x^{2} + 0.6 x = x

x = 2, x = 0

Solution steps

0.2 x^{2} + 0.6 x = x

Multiply both sides by

10

2 x^{2} + 6 x = x \cdot 10

Move

x 10

to the left side

2 x^{2} - 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 \cdot 0 = 4

x_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 2}

x = \frac{- ( - 4 ) + 4}{2 \cdot 2} : 2

x = \frac{- ( - 4 ) - 4}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 2, x = 0

3 x^{2} - 2 x - 1 = 0

x, 4 x - x^{2} = y

x, x^{2} + y^{2} = x y + 7

2 x^{2} + 14 x - 4 = - x^{2} + 3 x

x^{2} + 12 x - 27 = 6 x

What are the solutions to the equation 0.2x^2+0.6x=x ?
The solutions to the equation 0.2x^2+0.6x=x are x=2,x=0
Find the zeros of 0.2x^2+0.6x=x
The zeros of 0.2x^2+0.6x=x are x=2,x=0