What are the solutions to the equation solvefor x,4x-x^2=y ?

The solutions to the equation solvefor x,4x-x^2=y are x=2-sqrt(-y+4),x=sqrt(-y+4)+2

Find the zeros of solvefor x,4x-x^2=y

The zeros of solvefor x,4x-x^2=y are x=2-sqrt(-y+4),x=sqrt(-y+4)+2

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solve for

x, 4 x - x^{2} = y

x = 2 - - y + 4, x = - y + 4 + 2

Solution steps

4 x - x^{2} = y

Move

y

to the left side

4 x - x^{2} - y = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 4 x - y = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) ( - y )}{2 ( - 1 )}

Simplify

4^{2} - 4 (- 1) (- y) : 2 4 - y

x_{1, 2} = \frac{- 4 \pm 2 4 - y}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 4 - y}{2 ( - 1 )}, x_{2} = \frac{- 4 - 2 4 - y}{2 ( - 1 )}

x = \frac{- 4 + 2 4 - y}{2 ( - 1 )} : 2 - - y + 4

x = \frac{- 4 - 2 4 - y}{2 ( - 1 )} : - y + 4 + 2

The solutions to the quadratic equation are:

x = 2 - - y + 4, x = - y + 4 + 2

x, x^{2} + y^{2} = x y + 7

2 x^{2} + 14 x - 4 = - x^{2} + 3 x

x^{2} + 12 x - 27 = 6 x

x, 2 x^{2} - 5 x y + 2 y^{2} - 11 x - 7 y - 4 = 0

(- \frac{4}{3} b + \frac{9}{2})^{2} + b^{2} - (- \frac{4}{3} b + \frac{9}{2}) - 6 b = - 3

What are the solutions to the equation solvefor x,4x-x^2=y ?
The solutions to the equation solvefor x,4x-x^2=y are x=2-sqrt(-y+4),x=sqrt(-y+4)+2
Find the zeros of solvefor x,4x-x^2=y
The zeros of solvefor x,4x-x^2=y are x=2-sqrt(-y+4),x=sqrt(-y+4)+2