What are the solutions to the equation x^2+12x-27=6x ?

The solutions to the equation x^2+12x-27=6x are x=3,x=-9

Find the zeros of x^2+12x-27=6x

The zeros of x^2+12x-27=6x are x=3,x=-9

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x^{2} + 12 x - 27 = 6 x

x = 3, x = - 9

Solution steps

x^{2} + 12 x - 27 = 6 x

Move

6 x

to the left side

x^{2} + 6 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 27 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 27) = 12

x_{1, 2} = \frac{- 6 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 12}{2 \cdot 1}, x_{2} = \frac{- 6 - 12}{2 \cdot 1}

x = \frac{- 6 + 12}{2 \cdot 1} : 3

x = \frac{- 6 - 12}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 3, x = - 9

x, 2 x^{2} - 5 x y + 2 y^{2} - 11 x - 7 y - 4 = 0

(- \frac{4}{3} b + \frac{9}{2})^{2} + b^{2} - (- \frac{4}{3} b + \frac{9}{2}) - 6 b = - 3

2 y^{2} + 11 y + 12 = 0

x^{2} + 49 = - 14 x

4 (2 x - 1)^{2} = 8

What are the solutions to the equation x^2+12x-27=6x ?
The solutions to the equation x^2+12x-27=6x are x=3,x=-9
Find the zeros of x^2+12x-27=6x
The zeros of x^2+12x-27=6x are x=3,x=-9