What are the solutions to the equation x^2+49=-14x ?

The solutions to the equation x^2+49=-14x are x=-7

Find the zeros of x^2+49=-14x

The zeros of x^2+49=-14x are x=-7

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x^{2} + 49 = - 14 x

x = - 7

Solution steps

x^{2} + 49 = - 14 x

Move

14 x

to the left side

x^{2} + 49 + 14 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 14 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 49 = 0

x_{1, 2} = \frac{- 14 \pm 0}{2 \cdot 1}

x = \frac{- 14}{2 \cdot 1}

\frac{- 14}{2 \cdot 1} = - 7

x = - 7

The solution to the quadratic equation is:

x = - 7

4 (2 x - 1)^{2} = 8

(x) = - 10 x^{2} - 2500 x + 1000000

4 v^{2} - 15 v + 5 = - 3 v

x, x^{2} - 4 x y + 3 x + 25 y - 6 = 0

2 x^{2} + 13 x + 12 = (2 x + 3)^{2}

What are the solutions to the equation x^2+49=-14x ?
The solutions to the equation x^2+49=-14x are x=-7
Find the zeros of x^2+49=-14x
The zeros of x^2+49=-14x are x=-7