What are the solutions to the equation -2x^2+10x-12=0 ?

The solutions to the equation -2x^2+10x-12=0 are x=2,x=3

Find the zeros of -2x^2+10x-12=0

The zeros of -2x^2+10x-12=0 are x=2,x=3

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- 2 x^{2} + 10 x - 12 = 0

x = 2, x = 3

Solution steps

- 2 x^{2} + 10 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 2 ) ( - 12 )}{2 ( - 2 )}

1 0^{2} - 4 (- 2) (- 12) = 2

x_{1, 2} = \frac{- 10 \pm 2}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 10 + 2}{2 ( - 2 )}, x_{2} = \frac{- 10 - 2}{2 ( - 2 )}

x = \frac{- 10 + 2}{2 ( - 2 )} : 2

x = \frac{- 10 - 2}{2 ( - 2 )} : 3

The solutions to the quadratic equation are:

x = 2, x = 3

9 x^{2} + 4 x - 5 = 0

4 x^{2} + 16 x - 20 = 0

15 w^{2} - 14 w - 8 = 0

2 m^{2} + 3 m + 2 = 0

λ^{2} - 3 λ + 2 (1) = 0

What are the solutions to the equation -2x^2+10x-12=0 ?
The solutions to the equation -2x^2+10x-12=0 are x=2,x=3
Find the zeros of -2x^2+10x-12=0
The zeros of -2x^2+10x-12=0 are x=2,x=3