What are the solutions to the equation x^2+5x+6=1 ?

The solutions to the equation x^2+5x+6=1 are x=(-5+sqrt(5))/2 ,x=(-5-sqrt(5))/2

Find the zeros of x^2+5x+6=1

The zeros of x^2+5x+6=1 are x=(-5+sqrt(5))/2 ,x=(-5-sqrt(5))/2

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x^{2} + 5 x + 6 = 1

x = \frac{- 5 + 5}{2}, x = \frac{- 5 - 5}{2}

Decimal Notation

x = - 1.38196 \dots, x = - 3.61803 \dots

Solution steps

x^{2} + 5 x + 6 = 1

Move

1

to the left side

x^{2} + 5 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 5 = 5

x_{1, 2} = \frac{- 5 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 5}{2 \cdot 1}, x_{2} = \frac{- 5 - 5}{2 \cdot 1}

x = \frac{- 5 + 5}{2 \cdot 1} : \frac{- 5 + 5}{2}

x = \frac{- 5 - 5}{2 \cdot 1} : \frac{- 5 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 5}{2}, x = \frac{- 5 - 5}{2}

3 x^{2} - 9 x = 0

6 x^{2} + x - 10 = 2 x - 8

2 y^{2} + 36 = 0

- 0.1 x^{2} + 0.1 x = - 0.06

2 x^{2} - 5 x + 2 = 0

What are the solutions to the equation x^2+5x+6=1 ?
The solutions to the equation x^2+5x+6=1 are x=(-5+sqrt(5))/2 ,x=(-5-sqrt(5))/2
Find the zeros of x^2+5x+6=1
The zeros of x^2+5x+6=1 are x=(-5+sqrt(5))/2 ,x=(-5-sqrt(5))/2