What are the solutions to the equation -0.1x^2+0.1x=-0.06 ?

The solutions to the equation -0.1x^2+0.1x=-0.06 are x=-(-5+sqrt(85))/(10),x=(5+sqrt(85))/(10)

Find the zeros of -0.1x^2+0.1x=-0.06

The zeros of -0.1x^2+0.1x=-0.06 are x=-(-5+sqrt(85))/(10),x=(5+sqrt(85))/(10)

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- 0.1 x^{2} + 0.1 x = - 0.06

x = - \frac{- 5 + 85}{10}, x = \frac{5 + 85}{10}

Decimal Notation

x = - 0.42195 \dots, x = 1.42195 \dots

Solution steps

- 0.1 x^{2} + 0.1 x = - 0.06

Multiply both sides by

100

- 10 x^{2} + 10 x = - 6

Move

6

to the left side

- 10 x^{2} + 10 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 10 ) \cdot 6}{2 ( - 10 )}

1 0^{2} - 4 (- 10) \cdot 6 = 285

x_{1, 2} = \frac{- 10 \pm 2 85}{2 ( - 10 )}

Separate the solutions

x_{1} = \frac{- 10 + 2 85}{2 ( - 10 )}, x_{2} = \frac{- 10 - 2 85}{2 ( - 10 )}

x = \frac{- 10 + 2 85}{2 ( - 10 )} : - \frac{- 5 + 85}{10}

x = \frac{- 10 - 2 85}{2 ( - 10 )} : \frac{5 + 85}{10}

The solutions to the quadratic equation are:

x = - \frac{- 5 + 85}{10}, x = \frac{5 + 85}{10}

2 x^{2} - 5 x + 2 = 0

5 x^{2} - 40 x + 5 = 0

5 x^{2} - 4 x - 6 = x^{2} - 7

5 x^{2} = 10 x + 15

x, x^{2} - x y = 0

What are the solutions to the equation -0.1x^2+0.1x=-0.06 ?
The solutions to the equation -0.1x^2+0.1x=-0.06 are x=-(-5+sqrt(85))/(10),x=(5+sqrt(85))/(10)
Find the zeros of -0.1x^2+0.1x=-0.06
The zeros of -0.1x^2+0.1x=-0.06 are x=-(-5+sqrt(85))/(10),x=(5+sqrt(85))/(10)