What are the solutions to the equation solvefor x,x^2-xy=0 ?

The solutions to the equation solvefor x,x^2-xy=0 are x=y,x=0

Find the zeros of solvefor x,x^2-xy=0

The zeros of solvefor x,x^2-xy=0 are x=y,x=0

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solve for

x, x^{2} - x y = 0

x = y, x = 0

Solution steps

x^{2} - x y = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - y x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - y ) \pm ( - y ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

Simplify

(- y)^{2} - 4 \cdot 1 \cdot 0 : y

x_{1, 2} = \frac{- ( - y ) \pm y}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - y ) + y}{2 \cdot 1}, x_{2} = \frac{- ( - y ) - y}{2 \cdot 1}

x = \frac{- ( - y ) + y}{2 \cdot 1} : y

x = \frac{- ( - y ) - y}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = y, x = 0

3 x^{2} + 2 x + a x^{2} + 5 a + 1 = 0

x, (2 x + 3 y)^{2} = 20

- 3 x^{2} - 13 x + 2 = - 13

y, - 6 y^{2} - 21 = s (y^{2} + w)

x^{2} - 6 x + 7

What are the solutions to the equation solvefor x,x^2-xy=0 ?
The solutions to the equation solvefor x,x^2-xy=0 are x=y,x=0
Find the zeros of solvefor x,x^2-xy=0
The zeros of solvefor x,x^2-xy=0 are x=y,x=0