What are the solutions to the equation solvefor x,(2x+3y)^2=20 ?

The solutions to the equation solvefor x,(2x+3y)^2=20 are x=(2sqrt(5)-3y)/2 ,x=(-2sqrt(5)-3y)/2

Find the zeros of solvefor x,(2x+3y)^2=20

The zeros of solvefor x,(2x+3y)^2=20 are x=(2sqrt(5)-3y)/2 ,x=(-2sqrt(5)-3y)/2

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solve for

x, (2 x + 3 y)^{2} = 20

x = \frac{2 5 - 3 y}{2}, x = \frac{- 2 5 - 3 y}{2}

Solution steps

(2 x + 3 y)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 3 y = 20 : x = \frac{2 5 - 3 y}{2}

Solve

2 x + 3 y = - 20 : x = \frac{- 2 5 - 3 y}{2}

The solutions to the quadratic equation are:

x = \frac{2 5 - 3 y}{2}, x = \frac{- 2 5 - 3 y}{2}

- 3 x^{2} - 13 x + 2 = - 13

y, - 6 y^{2} - 21 = s (y^{2} + w)

x^{2} - 6 x + 7

3 x^{2} + 16 x + 17 = 0

0 = - 5 x^{2} + 8 x - 7

What are the solutions to the equation solvefor x,(2x+3y)^2=20 ?
The solutions to the equation solvefor x,(2x+3y)^2=20 are x=(2sqrt(5)-3y)/2 ,x=(-2sqrt(5)-3y)/2
Find the zeros of solvefor x,(2x+3y)^2=20
The zeros of solvefor x,(2x+3y)^2=20 are x=(2sqrt(5)-3y)/2 ,x=(-2sqrt(5)-3y)/2