What are the solutions to the equation 3x^2+16x+17=0 ?

The solutions to the equation 3x^2+16x+17=0 are x=(-8+sqrt(13))/3 ,x=-(8+sqrt(13))/3

Find the zeros of 3x^2+16x+17=0

The zeros of 3x^2+16x+17=0 are x=(-8+sqrt(13))/3 ,x=-(8+sqrt(13))/3

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3 x^{2} + 16 x + 17 = 0

x = \frac{- 8 + 13}{3}, x = - \frac{8 + 13}{3}

Decimal Notation

x = - 1.46481 \dots, x = - 3.86851 \dots

Solution steps

3 x^{2} + 16 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 3 \cdot 17}{2 \cdot 3}

1 6^{2} - 4 \cdot 3 \cdot 17 = 213

x_{1, 2} = \frac{- 16 \pm 2 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 16 + 2 13}{2 \cdot 3}, x_{2} = \frac{- 16 - 2 13}{2 \cdot 3}

x = \frac{- 16 + 2 13}{2 \cdot 3} : \frac{- 8 + 13}{3}

x = \frac{- 16 - 2 13}{2 \cdot 3} : - \frac{8 + 13}{3}

The solutions to the quadratic equation are:

x = \frac{- 8 + 13}{3}, x = - \frac{8 + 13}{3}

0 = - 5 x^{2} + 8 x - 7

(x) = 2600 + 2 x + 0.001 x^{2}

- 0.05 q^{2} + 700 = 10 q + 220

- 3 x^{2} + 363 = 0

7 x^{2} + 10 = 2 x

What are the solutions to the equation 3x^2+16x+17=0 ?
The solutions to the equation 3x^2+16x+17=0 are x=(-8+sqrt(13))/3 ,x=-(8+sqrt(13))/3
Find the zeros of 3x^2+16x+17=0
The zeros of 3x^2+16x+17=0 are x=(-8+sqrt(13))/3 ,x=-(8+sqrt(13))/3