What are the solutions to the equation 25d^2-60d+36=0 ?

The solutions to the equation 25d^2-60d+36=0 are d= 6/5

Find the zeros of 25d^2-60d+36=0

The zeros of 25d^2-60d+36=0 are d= 6/5

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25 d^{2} - 60 d + 36 = 0

d = \frac{6}{5}

Decimal Notation

d = 1.2

Solution steps

25 d^{2} - 60 d + 36 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 60 ) \pm ( - 60 ) ^{2} - 4 \cdot 25 \cdot 36}{2 \cdot 25}

(- 60)^{2} - 4 \cdot 25 \cdot 36 = 0

d_{1, 2} = \frac{- ( - 60 ) \pm 0}{2 \cdot 25}

d = \frac{- ( - 60 )}{2 \cdot 25}

\frac{- ( - 60 )}{2 \cdot 25} = \frac{6}{5}

d = \frac{6}{5}

The solution to the quadratic equation is:

d = \frac{6}{5}

x, x^{2} - 3 x = 0

8 w^{2} + 13 w + 4 = 3 w^{2}

x^{2} + b x + 1 = 0

4 x - 4 = x^{2}

- 4 x^{2} + 5 x + 5 = 0

What are the solutions to the equation 25d^2-60d+36=0 ?
The solutions to the equation 25d^2-60d+36=0 are d= 6/5
Find the zeros of 25d^2-60d+36=0
The zeros of 25d^2-60d+36=0 are d= 6/5