What are the solutions to the equation 8w^2+13w+4=3w^2 ?

The solutions to the equation 8w^2+13w+4=3w^2 are w=(-13+sqrt(89))/(10),w=(-13-sqrt(89))/(10)

Find the zeros of 8w^2+13w+4=3w^2

The zeros of 8w^2+13w+4=3w^2 are w=(-13+sqrt(89))/(10),w=(-13-sqrt(89))/(10)

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8 w^{2} + 13 w + 4 = 3 w^{2}

w = \frac{- 13 + 89}{10}, w = \frac{- 13 - 89}{10}

Decimal Notation

w = - 0.35660 \dots, w = - 2.24339 \dots

Solution steps

8 w^{2} + 13 w + 4 = 3 w^{2}

Move

3 w^{2}

to the left side

5 w^{2} + 13 w + 4 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

1 3^{2} - 4 \cdot 5 \cdot 4 = 89

w_{1, 2} = \frac{- 13 \pm 89}{2 \cdot 5}

Separate the solutions

w_{1} = \frac{- 13 + 89}{2 \cdot 5}, w_{2} = \frac{- 13 - 89}{2 \cdot 5}

w = \frac{- 13 + 89}{2 \cdot 5} : \frac{- 13 + 89}{10}

w = \frac{- 13 - 89}{2 \cdot 5} : \frac{- 13 - 89}{10}

The solutions to the quadratic equation are:

w = \frac{- 13 + 89}{10}, w = \frac{- 13 - 89}{10}

x^{2} + b x + 1 = 0

4 x - 4 = x^{2}

- 4 x^{2} + 5 x + 5 = 0

1 - 4 x - x^{2}

x^{2} - 13 x + 4 = 17

What are the solutions to the equation 8w^2+13w+4=3w^2 ?
The solutions to the equation 8w^2+13w+4=3w^2 are w=(-13+sqrt(89))/(10),w=(-13-sqrt(89))/(10)
Find the zeros of 8w^2+13w+4=3w^2
The zeros of 8w^2+13w+4=3w^2 are w=(-13+sqrt(89))/(10),w=(-13-sqrt(89))/(10)