What are the solutions to the equation x^2+6=-5x ?

The solutions to the equation x^2+6=-5x are x=-2,x=-3

Find the zeros of x^2+6=-5x

The zeros of x^2+6=-5x are x=-2,x=-3

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x^{2} + 6 = - 5 x

x = - 2, x = - 3

Solution steps

x^{2} + 6 = - 5 x

Move

5 x

to the left side

x^{2} + 6 + 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

x_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 1}{2 \cdot 1}, x_{2} = \frac{- 5 - 1}{2 \cdot 1}

x = \frac{- 5 + 1}{2 \cdot 1} : - 2

x = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = - 2, x = - 3

3 x^{2} - 30 x - 33 = 0

x, g = 3 x^{2} f

x^{2} - 3 x - 270 = 0

x^{2} + 3 x - 72 = 0

- 66.18 \cdot X^{2} - 2.46 \cdot X - 0.027 = - 12.5

What are the solutions to the equation x^2+6=-5x ?
The solutions to the equation x^2+6=-5x are x=-2,x=-3
Find the zeros of x^2+6=-5x
The zeros of x^2+6=-5x are x=-2,x=-3