What are the solutions to the equation x^2-3x-270=0 ?

The solutions to the equation x^2-3x-270=0 are x=18,x=-15

Find the zeros of x^2-3x-270=0

The zeros of x^2-3x-270=0 are x=18,x=-15

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x^{2} - 3 x - 270 = 0

x = 18, x = - 15

Solution steps

x^{2} - 3 x - 270 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 270 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 270) = 33

x_{1, 2} = \frac{- ( - 3 ) \pm 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 33}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 33}{2 \cdot 1}

x = \frac{- ( - 3 ) + 33}{2 \cdot 1} : 18

x = \frac{- ( - 3 ) - 33}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 18, x = - 15

x^{2} + 3 x - 72 = 0

- 66.18 \cdot X^{2} - 2.46 \cdot X - 0.027 = - 12.5

a^{2} + 14 a + 49 = 0

12 x^{2} - 4 x - 1 = 0

x^{2} - 15 x - 56 = 0

What are the solutions to the equation x^2-3x-270=0 ?
The solutions to the equation x^2-3x-270=0 are x=18,x=-15
Find the zeros of x^2-3x-270=0
The zeros of x^2-3x-270=0 are x=18,x=-15