What are the solutions to the equation a^2+14a+49=0 ?

The solutions to the equation a^2+14a+49=0 are a=-7

Find the zeros of a^2+14a+49=0

The zeros of a^2+14a+49=0 are a=-7

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a^{2} + 14 a + 49 = 0

a = - 7

Solution steps

a^{2} + 14 a + 49 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 49 = 0

a_{1, 2} = \frac{- 14 \pm 0}{2 \cdot 1}

a = \frac{- 14}{2 \cdot 1}

\frac{- 14}{2 \cdot 1} = - 7

a = - 7

The solution to the quadratic equation is:

a = - 7

12 x^{2} - 4 x - 1 = 0

x^{2} - 15 x - 56 = 0

y, x^{3} + 3 y^{2} z - x y z^{3} = 0

x^{2} + 10 x + 24 = 15

(x + 9)^{2} = 49

What are the solutions to the equation a^2+14a+49=0 ?
The solutions to the equation a^2+14a+49=0 are a=-7
Find the zeros of a^2+14a+49=0
The zeros of a^2+14a+49=0 are a=-7