What are the solutions to the equation m=x^2a+x^2b ?

The solutions to the equation m=x^2a+x^2b are x=sqrt(m/(a+b)),x=-sqrt(m/(a+b));\quad a+b\ne 0

Find the zeros of m=x^2a+x^2b

The zeros of m=x^2a+x^2b are x=sqrt(m/(a+b)),x=-sqrt(m/(a+b));\quad a+b\ne 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m = x^{2} a + x^{2} b

x = \frac{m}{a + b}, x = - \frac{m}{a + b}; a + b \neq = 0

Solution steps

m = x^{2} a + x^{2} b

Switch sides

x^{2} a + x^{2} b = m

Factor

x^{2} a + x^{2} b : x^{2} (a + b)

x^{2} (a + b) = m

Divide both sides by

a + b; a + b \neq = 0

x^{2} = \frac{m}{a + b}; a + b \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{m}{a + b}, x = - \frac{m}{a + b}; a + b \neq = 0

2 x^{2} + 6 = - 1, 3 x = 0

5 r^{2} - 80 = 0

2 x^{2} + 3 = - 5 x

16 x^{2} - 8 x - 1 = 0

5 x^{2} - 10 x + 13 = 0

What are the solutions to the equation m=x^2a+x^2b ?
The solutions to the equation m=x^2a+x^2b are x=sqrt(m/(a+b)),x=-sqrt(m/(a+b));\quad a+b\ne 0
Find the zeros of m=x^2a+x^2b
The zeros of m=x^2a+x^2b are x=sqrt(m/(a+b)),x=-sqrt(m/(a+b));\quad a+b\ne 0