What are the solutions to the equation -2x^2+14x-6=14 ?

The solutions to the equation -2x^2+14x-6=14 are x=2,x=5

Find the zeros of -2x^2+14x-6=14

The zeros of -2x^2+14x-6=14 are x=2,x=5

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- 2 x^{2} + 14 x - 6 = 14

x = 2, x = 5

Solution steps

- 2 x^{2} + 14 x - 6 = 14

Move

14

to the left side

- 2 x^{2} + 14 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 ( - 2 ) ( - 20 )}{2 ( - 2 )}

1 4^{2} - 4 (- 2) (- 20) = 6

x_{1, 2} = \frac{- 14 \pm 6}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 14 + 6}{2 ( - 2 )}, x_{2} = \frac{- 14 - 6}{2 ( - 2 )}

x = \frac{- 14 + 6}{2 ( - 2 )} : 2

x = \frac{- 14 - 6}{2 ( - 2 )} : 5

The solutions to the quadratic equation are:

x = 2, x = 5

7 x^{2} - 12 x + 3 = 0

3 x^{2} = 11 x - 6

x, x^{2} + y^{2} + 2 x - 6 y + 10 = 0

- 6 x^{2} - 7 x - 10 = - 6

3 x^{2} - 6 = 34 - 2 x^{2}

What are the solutions to the equation -2x^2+14x-6=14 ?
The solutions to the equation -2x^2+14x-6=14 are x=2,x=5
Find the zeros of -2x^2+14x-6=14
The zeros of -2x^2+14x-6=14 are x=2,x=5