What are the solutions to the equation 3x^2-(m+1)x+m-2=0 ?

The solutions to the equation 3x^2-(m+1)x+m-2=0 are x=(m-2)/3 ,x=1

Find the zeros of 3x^2-(m+1)x+m-2=0

The zeros of 3x^2-(m+1)x+m-2=0 are x=(m-2)/3 ,x=1

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3 x^{2} - (m + 1) x + m - 2 = 0

x = \frac{m - 2}{3}, x = 1

Solution steps

3 x^{2} - (m + 1) x + m - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - m - 1 ) \pm ( - m - 1 ) ^{2} - 4 \cdot 3 ( m - 2 )}{2 \cdot 3}

Simplify

(- m - 1)^{2} - 4 \cdot 3 (m - 2) : m - 5

x_{1, 2} = \frac{- ( - m - 1 ) \pm ( m - 5 )}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - m - 1 ) + m - 5}{2 \cdot 3}, x_{2} = \frac{- ( - m - 1 ) - ( m - 5 )}{2 \cdot 3}

x = \frac{- ( - m - 1 ) + m - 5}{2 \cdot 3} : \frac{m - 2}{3}

x = \frac{- ( - m - 1 ) - ( m - 5 )}{2 \cdot 3} : 1

The solutions to the quadratic equation are:

x = \frac{m - 2}{3}, x = 1

\frac{5 x ^{2}}{3} + 61 = 121

- 0.012 x^{2} + 220 = 0.001 x^{2} + 0.12 x + 220

12 x^{2} = 48

- 2 x^{2} + 10 x + 12 = 0

z^{2} - 5 z + 6 = 0

What are the solutions to the equation 3x^2-(m+1)x+m-2=0 ?
The solutions to the equation 3x^2-(m+1)x+m-2=0 are x=(m-2)/3 ,x=1
Find the zeros of 3x^2-(m+1)x+m-2=0
The zeros of 3x^2-(m+1)x+m-2=0 are x=(m-2)/3 ,x=1