What are the solutions to the equation -0.012x^2+220=0.001x^2+0.12x+220 ?

The solutions to the equation -0.012x^2+220=0.001x^2+0.12x+220 are x=0,x=-120/13

Find the zeros of -0.012x^2+220=0.001x^2+0.12x+220

The zeros of -0.012x^2+220=0.001x^2+0.12x+220 are x=0,x=-120/13

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- 0.012 x^{2} + 220 = 0.001 x^{2} + 0.12 x + 220

x = 0, x = - \frac{120}{13}

Decimal Notation

x = 0, x = - 9.23076 \dots

Solution steps

- 0.012 x^{2} + 220 = 0.001 x^{2} + 0.12 x + 220

Multiply both sides by

1000

- 12 x^{2} + 220000 = x^{2} + 120 x + 220000

Switch sides

x^{2} + 120 x + 220000 = - 12 x^{2} + 220000

Move

220000

to the left side

x^{2} + 120 x = - 12 x^{2}

Move

12 x^{2}

to the left side

13 x^{2} + 120 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 120 \pm 12 0 ^{2} - 4 \cdot 13 \cdot 0}{2 \cdot 13}

12 0^{2} - 4 \cdot 13 \cdot 0 = 120

x_{1, 2} = \frac{- 120 \pm 120}{2 \cdot 13}

Separate the solutions

x_{1} = \frac{- 120 + 120}{2 \cdot 13}, x_{2} = \frac{- 120 - 120}{2 \cdot 13}

x = \frac{- 120 + 120}{2 \cdot 13} : 0

x = \frac{- 120 - 120}{2 \cdot 13} : - \frac{120}{13}

The solutions to the quadratic equation are:

x = 0, x = - \frac{120}{13}

12 x^{2} = 48

- 2 x^{2} + 10 x + 12 = 0

z^{2} - 5 z + 6 = 0

7 x^{2} + 35 = 54 x

n^{2} - 7 n + 12 = 0

What are the solutions to the equation -0.012x^2+220=0.001x^2+0.12x+220 ?
The solutions to the equation -0.012x^2+220=0.001x^2+0.12x+220 are x=0,x=-120/13
Find the zeros of -0.012x^2+220=0.001x^2+0.12x+220
The zeros of -0.012x^2+220=0.001x^2+0.12x+220 are x=0,x=-120/13