What are the solutions to the equation 7x^2+35=54x ?

The solutions to the equation 7x^2+35=54x are x=7,x= 5/7

Find the zeros of 7x^2+35=54x

The zeros of 7x^2+35=54x are x=7,x= 5/7

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7 x^{2} + 35 = 54 x

x = 7, x = \frac{5}{7}

Decimal Notation

x = 7, x = 0.71428 \dots

Solution steps

7 x^{2} + 35 = 54 x

Move

54 x

to the left side

7 x^{2} + 35 - 54 x = 0

Write in the standard form

a x^{2} + b x + c = 0

7 x^{2} - 54 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 54 ) \pm ( - 54 ) ^{2} - 4 \cdot 7 \cdot 35}{2 \cdot 7}

(- 54)^{2} - 4 \cdot 7 \cdot 35 = 44

x_{1, 2} = \frac{- ( - 54 ) \pm 44}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 54 ) + 44}{2 \cdot 7}, x_{2} = \frac{- ( - 54 ) - 44}{2 \cdot 7}

x = \frac{- ( - 54 ) + 44}{2 \cdot 7} : 7

x = \frac{- ( - 54 ) - 44}{2 \cdot 7} : \frac{5}{7}

The solutions to the quadratic equation are:

x = 7, x = \frac{5}{7}

n^{2} - 7 n + 12 = 0

2 x^{2} + 24 x - 6 = 0

1.25 \cdot 1 0^{- 9} x^{2} + 20 \cdot 1 0^{- 6} x + 0.125 = 0

52 + 2 q = 100 - q^{2}

9 x^{2} + 27 x + 14 = 0

What are the solutions to the equation 7x^2+35=54x ?
The solutions to the equation 7x^2+35=54x are x=7,x= 5/7
Find the zeros of 7x^2+35=54x
The zeros of 7x^2+35=54x are x=7,x= 5/7