What are the solutions to the equation 6x(x+2)=-25x+35 ?

The solutions to the equation 6x(x+2)=-25x+35 are x= 5/6 ,x=-7

Find the zeros of 6x(x+2)=-25x+35

The zeros of 6x(x+2)=-25x+35 are x= 5/6 ,x=-7

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6 x (x + 2) = - 25 x + 35

x = \frac{5}{6}, x = - 7

Decimal Notation

x = 0.83333 \dots, x = - 7

Solution steps

6 x (x + 2) = - 25 x + 35

Expand

6 x (x + 2) : 6 x^{2} + 12 x

6 x^{2} + 12 x = - 25 x + 35

Move

35

to the left side

6 x^{2} + 12 x - 35 = - 25 x

Move

25 x

to the left side

6 x^{2} + 37 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 37 \pm 3 7 ^{2} - 4 \cdot 6 ( - 35 )}{2 \cdot 6}

3 7^{2} - 4 \cdot 6 (- 35) = 47

x_{1, 2} = \frac{- 37 \pm 47}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 37 + 47}{2 \cdot 6}, x_{2} = \frac{- 37 - 47}{2 \cdot 6}

x = \frac{- 37 + 47}{2 \cdot 6} : \frac{5}{6}

x = \frac{- 37 - 47}{2 \cdot 6} : - 7

The solutions to the quadratic equation are:

x = \frac{5}{6}, x = - 7

x, z = 4 - x^{2} - \frac{1}{4} y^{2}

3 c^{2} + c - 9 = - 2

12 x = - 9 x^{2} + 15

r^{2} + 2 r - 2 = 0

\frac{1}{4} x^{2} + 8 x - 1

What are the solutions to the equation 6x(x+2)=-25x+35 ?
The solutions to the equation 6x(x+2)=-25x+35 are x= 5/6 ,x=-7
Find the zeros of 6x(x+2)=-25x+35
The zeros of 6x(x+2)=-25x+35 are x= 5/6 ,x=-7